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A ball thrown by one player reaches the ...

A ball thrown by one player reaches the other in 2 seconds. The maximum height attained by the ball above the point of projection will be (g = 10`m//s^2`)

A

10m

B

7.5 m

C

5m

D

2.5m

Text Solution

Verified by Experts

The correct Answer is:
C
Given 2 = `(2u sin theta)//g` or `(usin theta)//g =1`
max height `(u^2 sin^2 theta)/(2g)g//2` or `((u^2sin^2 theta)//g^2) 10/2xx1^2 = 5m`
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