The range of a projectile fired at angle of `15^@` is 50m. If it is fired with the same speed at an angle of `45^@`, it's range will be

Options

A. 25 m
B. 50 m
C. 100 m
D. 77.6 m

Answer

C

Explanation

`u^2/gsin2xx12^@`=50 `u^2/g = 50/sin30 = 50/(1/2)` = 100
H.R = `u^2/gxxsin2xx45^@=u^2/g =100