A body is projected at angle `30^@` to the horizontal with kinetic energy E. The KE at the top most point is

Options

A. zero
B. E/4
C. E/2
D. 3E/4

Answer

D

Explanation

initial `K.E. E = 1/2mu^2`
K.E at the heighest point `= 1/2 (u cos theta)^2` = 1//2 m u^2 xx 3/4 = 3/4 E`.