A bomber diving at an angle of `30^@` with the horizontal releases a bomb at a height of 980m. The bomb is observed to strike the ground 4 s after it's release. What was the velocity of the bomber in m/s?

A bomber diving at an angle of 30^@ with the horizontal releases a bomb at a height of 980m. The bomb is observed to strike the ground 4 s after it's release.how far did the bomb travel horizontally during the flight ?

A body thrown with a velocity of 49 m/s at an single of 30^@ with the horizontal. Find (i) the maximam height attained by it, (ii) the time flight (iii) the horizontal range. What is the direction of its velocity after 2.5 sec. g =9.8 m/ s^2

From the top of a cliff 73.5 m a body is projected with a velocity of 19.6 m/s at an angle of 30^@ with the horizontal. Determine the time of flight, the distance from the foot of the tower and velocity with which the body strike the ground. g =9.8 m/ s^2

A projectile is thrown at an angle such that the horizontal and vertical velocities are 9.8m/s and 19.6m/s , it strikes at a point distance from point of throw as

A bomber plane moves horizontally with a speed of 500m s^-1 and a bomb releases from it , strikes the ground in 10S. Angle at which it strikes the ground will be (g=10m/s^2) .