If linear velocity of a body moving on the circumference of a circle be equal to the velocity acquired by a freely falling body by a distance equal to half of the radius of the circle, show that centrepetal acceleration is equal to the acceleration due to gravity.

Explanation

The magnitude of the velocity acquired by a freely falling body through distance
(r/2) is V= `sqrt(2gxxr/2)=sqrt(gr)`
The centripetal acceleration is `v^2/r=gr/r=g`