Find the proportion of work done in breaking a big spherical drop of water into n small spherical drops eac h of radius r

Explanation

`4/3 pi R^3 = n xx 4/3 pir^3`
`therefore r = R/n^(1/3)`
`therefore r^2 = R^2/(n^2/3)`
work done = `[4pinR^2/n^(2/3) - 4piR^2] T`
W = `4piR^2T[n^(1/3) - 1]`
`therefore` W = `n^(1/3)` -1