A particle performing S.H.M. has an acceleration of `100 cm/s^2`, when it is at a distance of 25 cm from the mean position. Calculate the period of SHM.

Explanation

"Acceleration"`=omega^2x=((2pi)/T)^2x`
T^2=(4pi^2x)/(Ac c^n)= (4xx9.87xx25)/100=9.87`
`therefore T=pi sec.`.