A particle performing S.H.M. has a velocity of 10 m/s, when it crosses the mean position. If the amplitude of oscillation is 2 m, then what is the velocity at midway between mean position and extreme position ?

Explanation

Velocity at mean position is maximum
`v_max=aomega`
`therefore 10=2xxomega`
` therefore omega=5`
v=omegasqrt(a^2-x^2) =5sqrt((2)^2-(1)^2)`
`=5xxsqrt3 m//s.`