A particle undergoes S.H.M. with a time period of 2 seconds. In how much time will it travel from its mean position to a displacement equal to half of its amplitude ?

Explanation

We know that `T=(2pi)/omega=2(thereforeomega=pi)`
When particle starts from mean position,
`x=asin omegat`
For `x=a/2`
` a/2=a sin omegat`
therefore 1/2=sin omegat=sin pit(there omega=pi)`
` therefore pit=pi/6`
`thereforet=1/6sec`