A particle performing S.H.M. starting from mean position has period 2 second and amplitude 5 cm. Then what is it's displacement at the end of half a second ?

Explanation

`x=asinomegat=asin((2pit)/T)`
`=5sin((2pi)/2xx1/2)=5 sin(pi/2)`
`5sin(pi/2)=5xx1=5cm`