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A particle performing S.H.M. has an acce...

A particle performing S.H.M. has an acceleration of `0.2 m//s^2` at a distance of 0.05 m from its mean position then what is it's time period ?

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`T=(2pi)/omega=(2pi)/sqrt(a//x)=(2xx3.14)/sqrt(0.2//0.05)=(2xx3.14)/sqrt4`
`=3.14 sec.`
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