A particle performing S.H.M. has a velocity of 10 m/s, when it crosses the mean position. If the amplitude of oscillation is 2 m, then what is the velocity at midway between mean position and extreme position ?

Explanation

`v=omegasqrt(a^2-x^2) = omegasqrt(a^2-(a/2)^2)`
` therefore x=a/2 `
`=omegasqrt((3a^2)/4)=(aomegasqrt3)/2=v_max/2sqrt3=(10sqrt3)/2`
` therefore v=5sqrt3 m/s.`