The distance travelled by a particle performing S.H.M. from its mean position in 2 second is equal to `sqrt3/2A`. Then what is its period ?

Explanation

`x=Asin omegat`
`sqrt(3A)/2=A sin omegatsqrt3/2=sin((2pi)/T)`
`thereforesin(pi/3)=sin((2pi)/2t)`
`pi/3=(2pi)/Txxt=(2pi)/Txx2`
`T=4xx3=12sec.`