6.5molal solution KOH, d = 1.89 `g//cm^3`, M =?

Calculate the volume of 8% by mass solution of NaOH (d = 1.34 g//cm^(3)) to prepare 500 ml of 4% by mass solution of NaOH (d = 1.24 g//cm^(3)) .

Density of aqueous solution of NaOH is 1.2 g//cm^3 , then find its molality [Given density of water = 1 g//cm^(3)

The density of 2M aqueous solution of NaOH is 1.28g//cm^(3) . The molality of the solution is [Given that molecular mass of NaOH=40gmol^(-1) ]

An aqueous solution of urea containing 18 g urea in 1500 cm^(3) of solution has a density of 1.5 g//cm^(3) . If the molecular weight of urea is 60. Then the molality of solution is:

Calculate the molarity of 3.3molal solution of KCl whose density is 1.28 g//ml

The density of 3 molal solution of NaOH is 1.110g mL^(-1) . Calculate the molarity of the solution.

An aqueous solution of urea containing 18 g urea in 1500 cm^3 of solution has a density of 1.052 g/ cm^3 . If the molecular weight of urea is 60, then the molality of solution is-

3.0 molal NaOH solution has a density of 1.110 g//mL . The molarity of the solution is:

A 1.24 M aqueous solution of KI has density of 1.15 g cm^(-3) . Answer the following questions about this solution: The molality of this solution will be