`lamda_1, lamda_2, lamda_3` are the first 3 lines of balmer series. Find `lamda_1//lamda_3`

If veca and vecb are two unit vectors perpendicular to each other and vecc=lamda_1veca+lamda_2vecb+lamda_3(vecaxxvecb) then the following is (are) true (A) lamda_1=veca.vecc (B) lamda_2=|vecbxxvecc| (C) lamda_3=|(vecaxxvecb)xxvecc| (D) lamda_1+lamda_2+lamda_3=(veca+vecb+vecaxxvecb).vecc

If lambda_(1), lamda_(2)and lamda_(3) are the wavelengths of the wave giving resonance with the fundamental, first and second overtones respectively of a closed orga pipe Then the ratio of wavelength lambda_(1), lamda_(2)and lamda_(3) is

Assertion : Two particles of de Broglie wavelength lamda_1 and lamda_2 combine to form a third particle of wavelength lamda_3 . Then , lamda_1 +lamda_2 =lamda_3 . Reason : If p_1,p_2 and p_3 are momenta of the three particles , respectively, then p_1+p_2=p_3 .

If veca,vecb,vecc are three non coplanar vectors such that vecr_1=veca-vecb+vecc,vecr_2=vecb+vecc-veca, vecr_3=vecc+veca+vecb,vecr=2veca-3vecb+3vecc if vecr=lamda_1 vecr_1+lamda_2vecr_2+lamda_3vecr_3 then (A) lamda_1=7/2 (B) lamda_1+lamda_2=3 (C) lamda_2+lamda_3=2 (D) lamda_1+lamda_2+lamda_3=4

Certain substance emits only the wavelengths lamda_1,lamda_2,lamda_3 and lamda_4 when it is at a high temperature, it will absorb only the following wavelengths

If lamda_(1) and lamda_(2) are the two valyes of lamda such that the alpha and beta of quadratic equation lamda(x^(2)-x)+x-5=0 satisfy (alpha)/(beta)+(beta)/(alpha)+(4)/(5)=0 then (lamda_(1))/(lamda_(2)^(2))+(lamda_(2))/(lamda_(1)^(2)) is equal to

The matrix A={:[(lamda_(1)^(2),lamda_(1)lamda_(2),lamda_(1)lamda_(3)),(lamda_(2)lamda_(1),lamda_(2)^(2),lamda_(2)lamda_(3)),(lamda_(3)lamda_(1),lamda_(3)lamda_(2),lamda_(3)^(2))]:} is idempotent if lamda_(1)^(2)+lamda_(2)^(2)+lamda_(3)^(2)=k where lamda_(1),lamda_(2),lamda_(3) are non-zero real numbers. Then the value of (10+k)^(2) is . . .

If lamda_1 " and " lamda_2 are the wavelengths of the first members of the Lyman and paschen series respectively, then lamda_1/lamda_2 is equal to