If L = 20.04 m `pm`0.01 m , B= 2.52 m `pm ` 0.02 m . What are the values of `(L xx B) and (L+B)` ?

Explanation

Given errors are absolute errors, while the rule says that percentage errors are to be added . Hence, the first step will be to convert the given absolut errors into percentage errors.
`L=20.04m+-(0.01)/(20.04)xx100%=20.04m+-0.05%`
`B=2.52m+-(0.02)/(2.52)xx100%=2.52m+-0.79%`
`LxxB=(20.04xx2.52)m^(2)+-(0.05+0.79)%=50.50m^(2)+-0.84%`
This is the result . However, since the data giben the question was in terms of absolute errors, so we should give our result also in absolute errors.
`LxxB=50.50m^(2)+-(0.84)/(100)xx50.50m^(2)=50.50m^(2)+-0.42m^(2)`