Solve with due regard to significant figures.
`46.7-10.4`
`(3.0xx10^(-8))+(4.5xx10^(-6))=`

Explanation

`46.7-10.04`
Here `46.7`has one decimal place , and `10.04`has two decimal places.
`:. 46.7-10.04=36.66`.
The result should have only one decimal place . The result is `36.7`.
`3.0xx10^(-8)+4.5xx10^(-6)=0.03xx10^(-6)=0.003xx10^(-6)+4.5xx10^(-6)=4.53xx10^(-6)`
here `4.5xx10^(-6)`has only one decimal place and `0.03xx10(-6)`can have two decimal places.
this result should be rounded off to one decimal place .
`:.(3.0xx10^(-8))+(4.5xx10^(-6))=4.5xx10^(-6)`