The kinetic energy of rotation `(E_k)` depends upon (i) angular momentum (J) : (ii) moment of inertia (i).
Find the relation by the method of dimensional analysis .

If J is the angular momentum and E is the kinetic energy, then (J^2)/E has the dimensions of

The K.E. of a body rotating at 300 rpm is 62.8 J. Its angular momentum is

Suppose, the torque acting on a body is given by tauT=KL+xl/omega . Where L = angular momentum, E moment of inertia, omega = angular speed. The dimensional formula for Kx is same as that for