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Total number of stereoisomers of the fol...

Total number of stereoisomers of the following compound is `CHCl=CH-CH(CH_(3))C_(2)H_(5)`

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
B
`CHCl = CH - undersetoverset(|)(CH_3)(C )H - C_2H_5` The compound has one double bond and one chiral centre. It forms two geometrical (cis and trans ) and two optical isomers. Hence the total number of isomers are four .
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Write IUPAC names of the following compounds : (CH_(3))_(2)C(C_(2)H_(5))_(2)

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Write IUPAC names of the following compounds. CH_(3)-CH=CH-CH_(2)-CH=CH-underset(C_(2)H_(5))underset(|)(CH)-CH_(2)-CH=CH_(2)

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Assign priority number to each of the following groups: (a) -CHO, -OH, -CH_(3), -CH_(2)OH (b) -CH = CH_(2), -CH_(2)CH_(3), - C_(6)H_(5), -CH_(3) (c ) (CH_(3))_(2)CH-,CI-,-CH_(2)CH_(2)Br

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Number of stereoisomers possible for BrCH_2 CH Cl CH_2 CH Cl CH_3Br

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AAKASH SERIES-ISOMERISM -ADDITIONAL PRACTICE EXERCISE (LEVEL-I(MAIN) STRAIGHT OBJECTIVE TYPE QUESTIONS)
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  7. Which of the following compounds can exhibit geometrical isomerism?

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