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The optical rotation of a solution of pu...

The optical rotation of a solution of pure natural camphor is found to be `+5.76^(@)` under the following conditions, concentration = 0.13g/ml, length of polarimeter = 1dm, wavelength = sodium D line, `T=25^(@)C`. The specific rotation of camphor is

A

`+44.3^@`

B

`+26.7^@`

C

`-26.7^@`

D

`-44.3^@`

Text Solution

Verified by Experts

The correct Answer is:
A
`[alpha]` = specific rotation of comphor
`((alpha) " = Observed angle of rotation" (theta))/(c xx 1)`
` = (+576)/(0.13 xx 1) = + 44.3^@`
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AAKASH SERIES-ISOMERISM -ADDITIONAL PRACTICE EXERCISE (LEVEL-I(MAIN) STRAIGHT OBJECTIVE TYPE QUESTIONS)
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