The volume of 1M NaOh required for complete neutralisation of 100ml of 1M of `H_3PO_3` & 100ml of 2M `H_3PO_2`

The exact volumes of 1 M NaOH solution required to neutralise 50 mL of 1 MH_(3) PO_(3) solution and 100 mL of 2 M H_(3)PO_(2) solution, respectively, are :

Volume (in ml) of 0.7 M NaOH required for complete reaction with 350 ml of o.3 M H_(3) PO_(3) solution is

Volume (in ml) 0f 0.7 M NaOH required for complete reaction with 350 ml of 0.3 M H_(3)PO_(3) solution is :

10ml of 1 M H_(2)SO_(4) will completely neutralise

What volume of 0.05 M Ca(OH)_(2) solution is needed for complete conversion of 10mL of 0.1 M H_(3)PO_(4) into Ca(H_(2)PO_(4))_(2) ?