`C_1 and C_2` are two curves intersecting at `(1,1) , C_1` satisfy `dy/dx=(y^2-x^2)/(2xy) and C_2` satisfy `dy/dx=(2xy)/(-y^2+x^2)` then area bounded by these two curves is

dy/dx=(2xy)/(x^2-1-2y)

(dy)/(dx) = (2xy)/(x^(2)-1-2y)

If (dy)/dx = (xy)/(x^2 + y^2), y(1) = 1 and y(x) = e then x =

xy=(x+y)^(n) and (dy)/(dx)=(y)/(x) thenn =1b.2c3d.4

The solution of (dy)/(dx)=(x^(2)+y^(2)+1)/(2xy) satisfying y(1)=1 is given by

The solution of (dy)/(dx)=(x^(2)+y^(2)+1)/(2xy) satisfying y(1)=0 is given by

The equation of the curve passing through the point (-1,-2) which satisfies (dy)/(dx) =-x^(2) -1/(x^(3)) is

Let C_(1) be the curve obtained by the solution of differential equation 2xy(dy)/(dx)=y^(2)-x^(2),xgt0 Let the curve C_(2) be the solution of (2xy)/(x^(2)-y^(2))=(dy)/(dx) . If both the curves pass through (1, 1), then the area enclosed by the curves C_(1) and C_(2) is equal to :