ABCD is a rectangle .It has 5,6,7,9 points on AD ,BC ,CD, AB respectively. if `alpha` is number of `Delta` formed by taking one point from each side and `beta` is number of quadrilaterals formed by one point from each side, then `abs(beta-alpha)=`

Consider a rectangle ABCD having 5, 7, 6, 9 points in the interior of the line segments AB, CD, BC, DA respectively. Let alpha be the number of triangles having these points from different sides as vertices and beta be the number of quadrilaterals having these points from different sides as vertices. Then (beta-alpha) is equal to :

The quadrilateral formed by joining the mid-points of the sides AB, BC, CD, DA of a quadrilateral ABCD is

Let ABCD be a rectangle. Let P, Q, R, S be the mid-points of sides AB, BC, CD, DA respectively. Then the quadrilateral PQRS is a

ABCD is a rectangle and P,Q,R and S are mid- points of the sides AB,BC,CD and DA respectively.Show that the quadrilateral PQRS is a rhombus.

If ABCD be a rectangle and P, Q, R, S be the mid-points of AB, BC, CD and DA respectively, then the area of the quadrilateral PQRS is equal to

A triangle ABC in which side AB,BC,CA consist 5,3,6 points respectively, then the number of triangle that can be formed by these points are

The sides of a triangle have 4, 5 and 6 interior points marked on them respectively. The total number of triangles that can be formed using any of these points

In the given figure,ABCD is a rectangle; E and F are the mid-points of the sides BC and CD respectively.What is the ratio of the area of Delta AEF and that of Delta ECF?

The diagonals of a quadrilateral ABCD are perpendicular.Show that the quadrilateral, formed by joining the mid-points of its sides,is a rectangle.