Two bodies begin to fall freely from the same height but the second falls T second after the first. The time (after which the first body begins to fall) when the distance between the bodies equals L is

Two bodies begin to fall freely from the same height. The second one begins to fall tau s after the first. The time after which the 2st body begins to fall, the distance between the bodies equals to l is

Two particles begin to fall freely from the same height but the second falls t_(0) second after the first. Find the time (after the dropping of first) when separation between the particles is h_(0) .

Two bodies begin a free fall from rest from the same height 2 seconds apart. How long after the first body begins to fall, the two bodies will be 40 m apart? ("Take g = 10ms"^(-2))

A body falls from a certain bhight. Two seconds later another body falls from the same height. How long after the beginning of motion of the first body is the distance between the bodies twice the distance at the moment the second body starts to fall ?

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g = 10 m//s^2.

A body falls freely from a height 'h' after two seconds if acceleration due to gravity is reversed the body

A body is released from a great height and falls freely towards the earth. Exactly one sec later another body is released. What is the distance between the two bodies 2 sec after the release of the second body ?

A stone is allowed to fall freely from rest. The ratio of the time taken to fall through the first metre and the second metre distance is

" The distances traveled by a body falling freely from rest in the first,second and third seconds are in the ratio "

A stone falls freely rest. The distance covered by it in the last second is equal to the distance covered by it in the first 2 s. The time taken by the stone to reach the ground is