For the given situation,the system is at rest,find the value of mass m :-

For the given situation as shown in the figure, the value of q theta keep the system in equilibrium will be

For the equilibrium of the system shown, the value of mass m should be

In the system shown in fig., all pulleys are mass less and the string is inextensible and light. (a) After the system is released, find the acceleration of mass m_(1) (b) If m_(1) = 1 kg, m_(2) = 2 kg "and" m_(3) = 3 kg then what must be value of mass m_(4) so that it accelerates downwards?

In Fig. initialy the system is at rest .Find out minimum value of F for which sliding start between the two blocks Given m_(A) = 10 kg and m_(B) = 20 kg

Consider a situation as shown in the figure. The system is released from rest. When the block of mass m has falled a distance L , its speed becomes (sqrt(gL))/(3) . Find the friction coefficient mu .

A man of mass 60kg is standing on a massless weighing machine. Find the weight of the man in different situations as shown in the following figures. Man holds the rope and the block is at rest. Man holds the rope and the system is at rest. Man holds the rope and the system is at rest.

In the given figure if system is released from rest,then find the minimum value of coefficient of friction such that block A of mass 2m does not move.

Consider the situation as shown in the figure. The boy of mass M holds the light rope and the system is at rest. If m is mass of the box, find the force exerted by the boy on the rope and contact force beteween the boy and the box.