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If 40.6g of a hydrocarbon contains \(4.2...

If 40.6g of a hydrocarbon contains \(4.2\times10^{23}\) molecules, then the hydrocarbon can be
\([N_{A}=6\times10^{23}\)]
\(C_{2}H_{2}\)
\(C_{3}H_{8}\)
\(C_{4}H_{10}\)
\(C_{2}H_{6}\)

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The formula of hydrocarbon is C_(4)H_(6) ? To which family does it belong ?

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