A thermally isolated vessel contains `100g` of water at `0^(@)C`. When air above the water is pumped out, some of the water freezes and some evaporates at `0^(@)C` itself. Calculate the mass of the ice formed such that no water is left in the vessel. Latent heat of vaporization of water at `0^(@)C=2.10xx10^(6)J//kg` and latent heat of fusion of ice `=3.36xx10^(5)J//kg`.

A thermally isolated vessel contains 100 g of water at 0^(@)C when air above the water is pumped out, some of the water freezes and some evaporates at 0^(@)C itself. Calculate the mass at 0^(@)C=2.10xx10^(6) j//kg and latent heat of fusion of ice =3.36xx10^(5) j//kg .

A thermally isolated vessel is maintained inside at 0^@C and contains 200 g of water. When the air above the water is pumped out, some of the water freezes while rest of it evaporated at 0^@C itself. Determine the mass of water that freezed. Take, Latent heat of vapourisation of water at 0^@C = 2.19 xx 10^3 J//g Latent heat of fusion of ice = 3.36 xx 10^2 J//g

A thermally insulated vessel contains 150g of water at 0^(@)C . Then the air from the vessel is pumped out adiabatically. A fraction of water turms into ice and the rest evaporates at 0^(@)C itself. The mass of evaporated water will be closest to : (Latent heat of vaporization of water =2.10xx10^(6)jkg^(-1) and Latent heat of Fusion of water =3.36xx10^(5)jkg^(-1) )

At 0^@C a thermally isolated container has 200 g of water. When air above water is pumped out, then some of water evaporates and some of it freezes. What will be the mass of ice formed on freezing when there will be no water left in container? Latent heat of vaporisation of water = 2.2 xx 10^6 J/kg and latent heat of fusion of ice = 3.37 xx 10^5 J/kg.

A copper calorimeter of mass 190 g contains 300 g of water at 0^(@)C and 50 g of ice at 0^(@)C .Find the amount of steam at 100^(@)C required to raise the temperature of this mixture by 10^(@)C . Given that the specific heat of copperis 420J//kg^(@)C , latent heat of vaporization of water is 2.25xx10^(5)xxJ//kg and latent heat of fusion of ice is 3.36xx10^(5)J//kg .

A non conducting vessel thermally insulated from its surroundings, contains 100 g of water 0^(@)C . The vessel is connected to a vacuum pump to pump to water vapour. As a result of this, some water is frozen. If the removal of water vapour is continued, what is the maximum amount of water that can be frozen in this manner? Laten heat of vaporisation of water =22.5xx10^(5)Jkg^(-1) and latent heat of fusion of ice =3.36xx10^(5)Jkg^(-1)

What is meant by saying that the latent heat of fusion of ice is 3.34 xx 10^(5)J//kg ?

A thermal insulated vessel contains some water at 0^(@)C . The vessel is connected to a vaccum pump to pum out water vapour. This results in some water getting frozen. It is given latent heat of vaporization of water at 0^(@)C = 21 xx 10^(5) J//kg and latent heat of freezing of water =3.36 xx 10^(5) J//kg . the maximum percentage amount of water vapour that will be solidified in this manner will be:

Find the result of mixing 1kg of ice at 0^(@)C with 1.5kg of water at 45^(@)C . (Specific latent heat of fusioin of ice =336xx10^(3)Jkg^(-1) )