If 1.71g of sugar (molarmass = 342) are dissolved in 500 cm3 of a solution at 300K, what will be its osmotic pressure? (R = 0.082 L bar `K^(-1) mol^(-1))`.

The osmotic pressure of solution containing 34.2 g of cane sugar (molar mass =342 g mol^(-1) ) in 1 L of solution at 20^(@)C is ______ ( given : R=0.082 L atm K^(-1)mol ^(-1) )

If 3 g of glucose ( molecular mas = 180 ) is dissolved in 60 mL water at 15^(@)C , then the osmotic pressure of this solution will be (R=0.0821 L atm K^(-1) mol ^(1)) _____.

An organicsubstance (M=169gmol^(-1)) isdissolved in 2000 cm3 of water. Its osmotic pressure at 12^@C was found to be 0.54 aim. If R = 0.0821 L atm K^(-1) mol^(-1) , calculate the mass of the solute.

The vapour pressure of acetone at 20^(@) C is 185 torr when 1.2 g of a non - volattile substance was dissolved in 100 g of acetone at 20^(@) C ,its vapour pressure was 183 torr . The molar mass ( g mol ^(-1) ) of the substance . is molar mass ( g mol ^(-1)) of the substance is ______.

At300 K,thesolutionof ureahasitsmolarity 0.1.Calculate the osmotic pressure of urea solution. Given that R = 0.082 Lbar K-1mol^(-1) .

The volume occupied by 1.8 g of water vapour at 374 ^@C and 1 bar pressure will be . [Use R = 0.083 ba r L K^(-1) mol^(-1) ]

0.6 g of a solute is dissolved in 0.1 L of a solvent , which develops an osmotic pressure of 1.23 atm 27^(@)C . The molar mass of the subsance is ___.

Calculate the temperature of 4.0 mol of a gas occupying 5 dm^3 at 3.32 bar. (R=0.083 bar dm^3 K^(-1) mol^(-1) )