What is the frequency and energy of a photon of wavelength 6000 `A^@` (Given h = `6.6 xx 10^(-34)` Js, `C = 3 xx 10^8 ms^(-1)`).

Explanation

Frequency v = `c/ lambda = (3 xx 10^8)/(6000 xx 10^(-10)) = 5 xx 10^14 Hz`
and energy = hv=`6.6 xx 10^-34 xx 5 xx 10^14 = 3.3 xx 10^-19 J`