For a photosensitive surface , work function is `3.3 xx 10^(-19)` J. Taking plank's constant to be `6.6 xx 10^(-34)` Js. Find threshold frequency.

Explanation

Here `W_0 = 3.3 xx 10 ^-19 J`
`h = 6.6 xx 10^-34 Js`
Threshold frequency `v_0 = W_0/h = (3.3 xx 10^-19)/(6.6 xx 10 ^-34) = 5 xx 10^14 Hz`