If a light of wavelength `4950 A^@`is viewed as a continuous flow of photons, what is the energy of each photon in eV? Given h = `6.6 xx 10^(-34) Js, C=3 xx 10^8 ms^(-1)`?

Explanation

Here `lambda = 4950 A^@ = 4950 xx 10^-10 m`
Energy of each photon `E= (hc)/lambda = (6.6 xx 10^-34 xx 3 xx 10^8)/(4950 xx 10^-10) = 4.0 xx 10^-19`
`= (4.0 xx 10^-19)/(1.6 xx 10^-19) = e V = 2.5 e V