An electron and proton are possessing same amount of kinetic energy. Which of the two has greater de Broglie wavelength ?

Explanation

de Brogile wavelength `lambda = h/sqrt(2mE)` where E is the kinetic energy of a particle of mass m. Given that E is same for electron and proton. So, `lambda prop 1/sqrtm`. Hence,`lambda` will be greater for smaller mass. Thus, de Broglie wavelength is greater for an electron.