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Two dice with faces 1,2,3,5,7,11 when ro...

Two dice with faces `1,2,3,5,7,11` when rolled . Find the probability that the sum of the top faces is less than or equal to `8`

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To find the probability that the sum of the top faces of two dice, each having faces labeled `1, 2, 3, 5, 7, 11`, is less than or equal to `8`, we can follow these steps: ### Step 1: Determine the total number of outcomes Each die has 6 faces, so when rolling two dice, the total number of outcomes is: \[ \text{Total Outcomes} = 6 \times 6 = 36 \] ### Step 2: Identify the favorable outcomes We need to find all the combinations of the two dice where the sum of the top faces is less than or equal to `8`. We will systematically check each possible outcome: - **When the first die shows 1:** - \(1 + 1 = 2\) - \(1 + 2 = 3\) - \(1 + 3 = 4\) - \(1 + 5 = 6\) - \(1 + 7 = 8\) - \(1 + 11 = 12\) (not valid) **Favorable outcomes:** (1,1), (1,2), (1,3), (1,5), (1,7) → 5 outcomes - **When the first die shows 2:** - \(2 + 1 = 3\) - \(2 + 2 = 4\) - \(2 + 3 = 5\) - \(2 + 5 = 7\) - \(2 + 7 = 9\) (not valid) - \(2 + 11 = 13\) (not valid) **Favorable outcomes:** (2,1), (2,2), (2,3), (2,5) → 4 outcomes - **When the first die shows 3:** - \(3 + 1 = 4\) - \(3 + 2 = 5\) - \(3 + 3 = 6\) - \(3 + 5 = 8\) - \(3 + 7 = 10\) (not valid) - \(3 + 11 = 14\) (not valid) **Favorable outcomes:** (3,1), (3,2), (3,3), (3,5) → 4 outcomes - **When the first die shows 5:** - \(5 + 1 = 6\) - \(5 + 2 = 7\) - \(5 + 3 = 8\) - \(5 + 5 = 10\) (not valid) - \(5 + 7 = 12\) (not valid) - \(5 + 11 = 16\) (not valid) **Favorable outcomes:** (5,1), (5,2), (5,3) → 3 outcomes - **When the first die shows 7:** - \(7 + 1 = 8\) - \(7 + 2 = 9\) (not valid) - \(7 + 3 = 10\) (not valid) - \(7 + 5 = 12\) (not valid) - \(7 + 7 = 14\) (not valid) - \(7 + 11 = 18\) (not valid) **Favorable outcomes:** (7,1) → 1 outcome - **When the first die shows 11:** - All combinations exceed 8. **Favorable outcomes:** None → 0 outcomes ### Step 3: Count the total number of favorable outcomes Now, we add up all the favorable outcomes: \[ 5 + 4 + 4 + 3 + 1 + 0 = 17 \] ### Step 4: Calculate the probability The probability \(P\) that the sum of the top faces is less than or equal to `8` is given by: \[ P = \frac{\text{Number of Favorable Outcomes}}{\text{Total Outcomes}} = \frac{17}{36} \] ### Final Answer The probability that the sum of the top faces is less than or equal to `8` is: \[ \frac{17}{36} \] ---
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