The line 2x-y+1=0 is tangent to the circ...

The line `2x-y+1=0` is tangent to the circle at the point (2, 5) and the center of the circle lies on `x-2y=4.` The radius of the circle is

A

`3sqrt(5)`

B

`5sqrt(3)`

C

`2sqrt(5)`

D

`5sqrt(2)`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is :

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4 The radius of the circle is:

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the center of the circle lies on x-2y=4. Then find the radius of the circle.

The line 2x-y+1=0 is tangent to the circle at the point (2, 5) and the centre of the circle lies on x-2y=4. The square of the radius of the circle is

The line 2x-y+1=0 touches a circle at the point (2, 5) and the centre of the circle lies on x-2y=4 . The diameter (in units) of the circle is

If the line 2x-y+1=0 touches the circle at the point (2,5) and the centre of the circle lies in the line x+y-9=0. Find the equation of the circle.

The line 5x-y=3 is a tangent to a circle at the point (2,7) and its centre is on theline x+2y=19. Find the equation of the circle.

If the line x+3y=0 is the tangent at (0,0) to the circle of radius 1, then the centre of one sum circle is