`veca=alphahati+beta hatj-3hatk , vecb=-beta hati-alphahatj+hatk , vecc=hati-2hatj+hatk` where `veca*vecb=1 , vecb*vecc=-3` then find `1/3(vecaxxvecb)*vecc`

veca=hati+hatj+hatk , vecb=hati-hatk , veca xx vecc = vecb , veca*vecc=3 then Find [(veca,vecb,vecc)]

If veca=2hati+3hatj+hatk, vecb=hati-2hatj+hatk and vecc=-3hati+hatj+2hatk , then [veca vecb vecc]=

If veca = 2 hati - 3hatj, vecb = hati + hatj -hatk, vecc = 3hati - hatk, find [a vecb vecc]

If veca=7hati+3hatj-6hatk , vecb=2hati+5hatj-hatk and vecc=-hati+2hatj+4hatk . Find (veca-vecb)xx(vecc-vecb) .

if veca=hati-hatj-3hatk, vecb=4hati-3hatj+hatk and vecc=2hati+hatj+2hatk, verify that vecaxx(vecb+vecc)=vecaxxvecb+vecaxxvecc

Given veca=xhati+yhatj+2hatk,vecb=hati-hatj+hatk , vecc=hati+2hatj, veca botvecb,veca.vecc=4 then

Let veca=alphahati+2hatj- 3hatk, vecb=hati+ 2alphahatj - 2hatk and vecc = 2hati - alphahatj + hatk . Find the value of 6 alpha . Such that {(vecaxxvecb)xx(vecbxx vecc)}xx(veccxxveca)=0

If veca=2hati+2hatj-hatk, vecb=3hati-hatj-hatk and vecc=hati+2hatj-3hatk then verify that vecaxx(vecbxxvecc)=(veca.vecc)vecb-(veca.vecb)vecc .