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(y – 3)^2 = y^2 – 9...

`(y – 3)^2 = y^2 – 9`

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Draw the rough sketch and find the area of the region : {(x, y) : 9 x^2 + y^2 le 9, 3 x + y ge 3} .

Factorise : 9x^2 y^2 – 16

Calculate the area of the region enclosed between the circles: (iii) x^2+y^2=9 , (x-3)^2+y^2=9

Find the area bounded by the region given by : A = {(x,y) : x^2/9 + y^2/4 le 1 le x/3+y/2} .

Find the area bounded by the region given by : A = {(x,y) : x^2/25 + y^2/9 le 1 le x/5+y/3} .

Find the area bounded by the region given by : A = {(x,y) : x^2/16 + y^2/9 le 1 le x/4+y/3} .

Add : 4y (3y^2 + 5y – 7) and 2 (y^3 – 4y^2 + 5)

The area of the circle x^2 + y^2 = 9 is :

Solve for the value of x : (2y + 3)/(y-9) = 2/7