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A steel ball of mass 0.1 kg falls from a...

A steel ball of mass 0.1 kg falls from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball, find the rise in temperature of the ball ? (specific heat of steel `= 460 JKg^(-1)K^(+) , g = 10 ms^(-2))`

Text Solution

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Loss in gravitational PE = Heat energy ,
`0.1 xx 10(10 - 5.4) = 0.1 xx 460 xx Delta theta`
`implies Deltatheta = 0.1^(0)C` (rise in temperature)
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