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10 beggars are sitting in a row. The num...

10 beggars are sitting in a row. The number of ways in which a person having 4 one rupec coins (like), and 6 two rupee coins (like), can give away all coins to them so that each gets one coin and no two adjacent beggars will get one rupee coins. (Hint : By calling one rupee coin as A and two rupee coin as B, we have to arrange AAAABBBBBB so that no two A's are together)

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The correct Answer is:
`("^7P_4)/(4!)`
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