Simplify `""^(34)C_(5)+ overset(4) underset(r=0)Sigma ""^((38-r))C_(4)`.

overset(10)underset(r=0)sum^(40-r)C_(5) is equal to

""^(47 ) C_(4 )+ underset( j =1) overset( 5 ) sum ""^((52- j)) C_(3)=

int (overset(oo)underset(r=o)sum(x^(r)2^(r))/(r!))dx=

the value of ""^50C_(4) + underset( r=1) overset( 6 ) sum ""^(56 - r) C_(3) is

underset(n=0)overset(oo)Sigma(1)/((n+1)!)=

Simplify ""^(34)C_(5)+ Sigma_(r=0)^(4) ""^((38-r))C_(4) .

.^(37)C_(4)+underset(r = 1)overset(5)sum(42- r)_(C_(3))=

If S_(n) = underset (r=0) overset( n) sum (1) /(""^(n) C_(r)) and T_(n) = underset(r=0) overset(n) sum (r )/(""^(n) C_(r)) then (t_(n))/(s_(n)) =