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If X = {4^(n) - 3n - 1: n in N} " and " ...

If `X = {4^(n) - 3n - 1: n in N} " and " Y = {9(n-1): n in N}`, where N is the set of natural numbers, then `X cup Y` is equal to

A

X

B

Y

C

N

D

R

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The correct Answer is:
B
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AAKASH SERIES-SETS AND RELATIONS -PRACTICE EXERCISE
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