Let 's subtract.
(-mn-m+n) from (4mn + m+n)`

Using formula let's show that. (3m + 4n)^2 = (3m - 4n)^2 + 48mn

Let's factorise (8m^3 + 12m^2n + 6mn^2 + n^3)

Let's multiply :- (-2mn) xx frac(1)(6) m^2n^2 xx 13 m^4n^4

Let's write the value of (m^2 + n^2) (m^3 + n^3) by calculation if m + n = 5 and mn = 6.

The number of ways in which we can distribute m n students equally among m sections is given by a. ((m n !))/(n !) b. ((m n)!)/((n !)^m) c. ((m n)!)/(m ! n !) d. (m n)^m

Let's resolve into factor:- 6m^2 - 11mn - 10n^2

Let's resolve into factors the following agebraic expressions : - m^3 - n^3 -m(m^2-n^2) + n(m-n)^2

IfI_(m , n)=int_0^(pi/2)sin^m xcos^n xdx , Then show that I_(m , n)=(m-1)/(m+n)I_(m-2,n)(m ,n in N) Hence, prove that I_(m , n)=f(x)={((n-1)(n-3)(m-5)(n-1)(n-3)(n-5))/((m+n)(m+n-2)(m+n-4))pi/4 when both m and n are even ((m-1)(m-3)(m-5)(n-1)(n-3)(n-5))/((m+n)(m+n-2)(m+n-4))}

Let T_(r) be the rth term of an A.P. If m. T_(m) = n.T_(n) , the show that, T_(m+n) = 0 .

Let A and B be two sets consisting of m and n elements respectively (n ge m) . The number of one - one functions from A to B is