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Simplify the (a^2+b^2)(a^2-b^2)+(b^2+c^2...

Simplify the `(a^2+b^2)(a^2-b^2)+(b^2+c^2)(b^2-c^2)+(c^2+a^2)(c^2-a^2)`

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Let's simplify:- a^2(b^2 - c^2) + b^2 (c^2 - a^2) + c^2 (a^2 - b^2)

If D is the mid-point of the side B C of triangle A B C and A D is perpendicular to A C , then 3b^2=a^2-c ^2 (b) 3a^2=b^2 3c^2 b^2=a^2-c^2 (d) a^2+b^2=5c^2

Factorise : (a^(2)-b^(2))(a+b)+(b^(2)-c^(2))(b+c)+(c^(2)-a^(2))(c+a)

If a,b,c are in H.P , b,c,d are in G.P and c,d,e are in A.P. , then the value of e is (a) (ab^(2))/((2a-b)^(2)) (b) (a^(2)b)/((2a-b)^(2)) (c) (a^(2)b^(2))/((2a-b)^(2)) (d) None of these

Simplify : ((x^a)/(x^b))^(a^2+ab+b^2)xx((x^b)/(x^c))^(b^2+bc+c^2)xx((x^c)/(x^a))^(c^2+ca+a^2) .

Factorise : b^(2)c^(2)(b^(2)-c^(2))+c^(2)a^(2)(c^(2)-a^(2))+a^(2)b^(2)(a^(2)-b^(2))

Show that: abs(((b+c)^2,a^2,bc) , ((c+a)^2,b^2,ca) , ((a+b)^2,c^2,ab))=(a^2+b^2+c^2)(a+b+c)(b-c)(c-a)(a-b)

(bz+cy)/a=(cx+az)/b=(ay+bx)/c then prove x/(a(b^2+c^2-a^2))=y/(b(c^2+a^2-b^2))=z/(a(a^2+b^2-c^2))

Simplify root(3)(a^(-2)).b xx root(3)(b^(-2)).c root(3)(c^(-2)).a .

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