Light travels 186000 in 1 second. Again 1 mile = 1.6093 km, let's find the distance travelled by light in 1 second in Kilometers approximately (upto 3 decimal place of approximation.).

Let's find the approximate value of 12/13 up to 2,3,4 & 5 decimal places.

Let's find the approximate value of 1.21428571 up to four decimal places.

Let's find the approximate value of the following sqrt6 (upto 3 decimal places).

Let's find the approximate value of the following sqrt8 (upto 2 decimal places).

Let's find the approximate value of the following sqrt11 (upto 2 decimal places)

Let's find the approximate value of the following sqrt12 (upto 2 decimal places).

Length of line segment is 1.59 cm, let us find what is the approximate value of the length.

A particle moves with uniform acceleration and the distance travelled in t - th second is s_(t) = 3 + 2t . Find the initial velocity of the particle .

If the speed of light is 3.0xx10^(8)m*s^(-1) , calculate the distance covered by light in 2.00 ns.

In a system of units the units of length is defined as the distance travelled by light in space in 1 s and the unit of time taken by the earth to revolve round the sun once. Find the velocity unit in CGS system.