Moles of Methylbromide required to form 23g Trimethylbenzyl ammonium bromide is nx`10^(-1)`. Calculate n

How many moles of methyl iodide would he required to form quatermary ammonium salt when treated with a secondary amine ?

A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are nxx10^(-1) , when n= __________ . (Round off to the Nearest Integer). [ Given : Atomic : C 12.0 u, H: 1.0 u, N:14.0u, Br :80.0 u]

(a)How many moles are present in 11.5g of sodium? (b)The mass of an atom of element (X) is 2.0xx10^(-23)g . Calculate its atomic mass.

Calculate the number of moles of methane required to produce 33 g of carbon dioxide gas on its complete combustion.

In an attempt to prepare propane by Wurtz reaction 1 mole of methyl bromide and 1 mole of ethyl bromide are treated with sodium. Assuming equal probability for all possible reaction. How many g of propane will be obtained?

The heat of ionisation of formic acid is 1.5 kJ/ mo. 9.2 g formic acid on reaction with 7 g ammonium hydroxide gives 10.8 kJ of heat. Calculate the heat of ionisation of ammonium hydroxide. (1cal=4.2J)