Velocity of a particle moving in a stright line varies with its displacement as `v=(sqrt(4+4s))m//s`. Find its displacement in the first 2 seconds of its motion

Explanation

Squaring the given equation, we get `v^(2)=4+4s`
Now , comparing it with `v^(2)=u^(2)+2as`
we get, `u=2m//s "and" a=2m//s^(2)`
therefore , Dispalcement `t=2s`is
`s=ut+1/2at^(2)"or"s=(2)(2)+1/2(2)(2)^(2)"or"s=8m`