Five kg of air is heated at constant volume. The temperature of air increase from 300K to 340K. If the specific heat at constant volume is 0.169 kcal/kg K, find the amount of heat absorbed.

Explanation

`m=5kg,dT=340-300=40K` ,
`C_(v)=0.169 kcal/kg K`,
Principal specific heat at constant volume `C_(v)=(dQ)/(mdT)`
The amount of heat absorbed, `dQ=mC_(v)dT=5xx0.169xx40=33.8 kcal` .