When 5 moles of an ideal gas is compressed isothermally, its volume decreases from 5 litre to 1 litre. If the gas is at `27^(@)`C, find the work done on the gas.

Explanation

In the case .n. moles, work done on the gas
`W=nRT log_(e) [V_(2)/V_(1)] W=nRTxx2.3026xxlog_(10)[V_(2)/V_(1)]`
`R=8.314 " J mole" ^(-1)K^(-1)`
`T=27+273=300 K, V_(1)=1 litre=10^(-3)m^(3)`
` :. V_(2)=5 litre= 5xx10^(-3)m^(3) rArr V_(2)/V_(1)=1/5`
` :. W=5xx8.314xx300xx2.3026xxlog_(10)[1/5]`
`=5xx8.314xx300x2.3026xx(-0.6990)`
`-2.007xx10^(4)J`