If a, b, c are the sides of DeltaABC, i...

If a, b, c are the sides of `DeltaABC`, inscribed in a given circle, then `(deltaa)/(CosA)+(deltab)/(CosB)+(deltac)/(CosC)=`

A

0

B

`a+b+c`

C

`A+B+C`

D

2R

Text Solution

Verified by Experts

The correct Answer is:

A

Promotional Banner

Promotional Banner

Recommended Questions

If a, b, c are the sides of DeltaABC, inscribed in a given circle, th...
Text Solution
|
If in DeltaABC,(cosA)/(a)=(cosB)/(b)=(cosC)/(c) and side a=2, then th...
Text Solution
|
In a DeltaABC,((b)/(c)+(c)/(b))cosA+((a)/(b)+(b)/(a))cosC+((a)/(c)+(c)...
Text Solution
|
In DeltaABC,(cosA)/(a)+(cosB)/(b)+(cosC)/(c)=
Text Solution
|
ln a DeltaABC, if (cosA)/a=(cosB)/b=(cosC)/c and the side a = 2, then ...
Text Solution
|
In DeltaABC if (cosA)/a=(cosB)/b=(cosC)/c Prove that DeltaAB C is equi...
Text Solution
|
In DeltaABC if (cosA)/a=(cosB)/b=(cosC)/c Prove that DeltaAB C is equi...
Text Solution
|
In DeltaABC,a/cosA=b/cosB=c/cosC,ifb=2 then the area of the triangle i...
Text Solution
|
সরল করো : 1+(sin(A-B))/(cosA cosB)+(sin(B-C))/(cosB cosC)+(sin(C-A))/(...
Text Solution
|