If tanx = (2b)/(a-c) , a ne c, y = a cos...

If `tanx = (2b)/(a-c) , a ne c, y = a cos^2 x + 2b sinx.cos x + c sin^2 x z = a sin^2 x -2b sinx.cos x+"c" cos ^2x` then

A

y = z

B

y - z = a + c

C

y - z = a - c

D

`y - z = (a-c)^(2) + 4b^(2)`

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The correct Answer is:

C

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