Suppose "cos" (2pi)/(7) + "cos" (4pi)/(7...

Suppose `"cos" (2pi)/(7) + "cos" (4pi)/(7) + "cos" (6pi)/(7) = - (1)/(2) and "cos" (2pi)/(7) "cos"(4pi)/(7) "cos" (6pi)/(7) = - (1)/(8)`, then the numerical value of `"cosec"^(2) (pi)/(7) + "cosec"^(2)(2pi)/(7) + "cosec"^(2) (3pi)/(7)` must be

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The correct Answer is:

8

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